Alternating Current Circuits

Unlike DC, an AC supply never sits still — its voltage sweeps from zero to a peak and back, then reverses, tracing a sine wave every cycle. Push that wave through a resistor, a coil, and a capacitor in turn, and each one treats it completely differently. Watch how.

Act 1 · The Alternating Wave & Measuring It

Voltage and current climb, fall, reverse, and repeat

An AC voltage is written v = Vmax sinωt. Egypt's mains run at 50 Hz — fifty full cycles every second. An ordinary moving-coil meter can't track a current that reverses that fast, so a hot wire ammeter instead measures the heating effect, which never reverses since Q ∝ I².

θ V v = Vᵤₓᵮ sin ωt hot wire ammeter — needle settles at the effective (rms) value
v = 0 V · i = 0 A · effective (rms) I = 0 A
Peak voltage, Vᵤₓᵮ200 V
Resistance, R40 Ω
Frequency, f50 Hz
Higher f spins the wave faster; the hot wire's reading is unaffected.

Now send that same wave through a plain resistor and watch how voltage and current line up.

Act 2 · A Non-Inductive Ohmic Resistor

Voltage and current stay perfectly in step

v = Vmaxsinωt and i = V/R = Imaxsinωt rise and fall together — they reach zero, peak, and reverse at exactly the same instants. Voltage and current are in phase.

voltage & current, same phase solid: V · dashed: I V I current & voltage vectors: 0° apart
i = V/R = 0 A
Peak voltage, Vᵤₓᵮ200 V
Resistance, R40 Ω

An inductor of zero resistance behaves nothing like this — its current lags the voltage.

Act 3 · An Inductive Coil of Zero Resistance

The coil fights every change in current, so voltage leads by 90°

The coil's self-induced back-emf, -LΔI/Δt, opposes the supply. Since ΔI/Δt is the slope of the current curve, the voltage waveform turns out to be a quarter-cycle ahead of the current: the voltage leads the current by 90°.

voltage leads current by 90° solid: V · dashed: I I V 90° V vector 90° ahead of I
Xᵟ = 2πfL = 0 Ω · I = V/Xᵟ = 0 A
f Xᵟ
Peak voltage, Vᵤₓᵮ200 V
Inductance, L0.10 H
Frequency, f50 Hz

A capacitor swings the other way entirely — its voltage lags the current.

Act 4 · A Capacitor

Charge builds first, so current leads and voltage lags by 90°

Current i = CΔV/Δt depends on how fast the plate voltage is changing — fastest right when V crosses zero. The current wave therefore runs a quarter-cycle ahead of the voltage: the voltage lags the current by 90°.

voltage lags current by 90° solid: V · dashed: I I V 90° V vector 90° behind I
XC = 1/(2πfC) = 0 Ω · I = V/XC = 0 A
f, C XC
Peak voltage, Vᵤₓᵮ200 V
Capacitance, C50 μF
Frequency, f50 Hz

Mix resistance with reactance in one series circuit, and the vectors have to be added properly — that's impedance.

Act 5 · Impedance of RL, RC and LCR Circuits

Voltages can't be added algebraically — only as vectors

In series, the same current runs through every part, but each part's voltage sits at a different phase. Adding VR, VL and VC algebraically overshoots the real supply voltage; adding them as vectors gives Z = √(R² + (Xᵟ − XC)²).

circuit is inductive R along the base, reactance vertical, Z the hypotenuse
Z = 0 Ω · tanθ = 0 · θ = 
Resistance, R40 Ω
Inductive reactance, Xᵟ30 Ω
Capacitive reactance, XC20 Ω

The coil and capacitor store and return energy — they consume no power. Only R turns electrical energy into heat.

Take away the resistor entirely, and a coil and capacitor left alone will slosh energy back and forth forever — an oscillating circuit.

Act 6 · The Oscillating (LC) Circuit

Energy trades places between the capacitor's field and the coil's field

A charged capacitor discharges through an inductor. As its charge falls, the coil's current rises, storing the energy as a magnetic field. When the charge hits zero, the coil's collapsing field drives the current onward, recharging the capacitor with reversed polarity — and the cycle repeats at f = 1/(2π√(LC)).

capacitor inductor solid: charge q(t) · dashed: current i(t)
f = 1/(2π√LC) = 0 Hz
Inductance, L16 μH
Capacitance, C4.9 mF
Smaller L and C mean faster energy exchange, higher f.

Feed that oscillating circuit a range of frequencies and one stands out sharply — the resonance point used to tune a radio.

Act 7 · Resonance & the Tuned Circuit

When Xᵟ equals XC, the current in the circuit peaks

Sweep the AC supply's frequency across an LCR circuit and the current is small when far from f₀ = 1/(2π√LC), and largest exactly at f₀, where the inductive and capacitive reactances cancel. A radio receiver tunes its variable capacitor until the station's frequency matches f₀ and only that station's signal passes through.

frequency, f Z (grey-red) & current I (orange), swept over f
f₀ = 0 Hz · f = 0 Hz · Z = 0 Ω · I = 0 A
Resistance, R50 Ω
Inductance, L10 mH
Capacitance, C2.6 nF
Supply frequency, f980 kHz
Slide toward f₀ and the current climbs to its peak — that's the station tuned in.
In a nutshell
  • Alternating current: v = Vmaxsinωt, reversing direction every half cycle; Egypt's mains run at 50 Hz.
  • Hot wire ammeter: reads the effective (rms) value via the heating effect, Q ∝ I² — direction-independent, non-uniform scale.
  • Resistor: V and I in phase.
  • Inductor: Xᵟ = 2πfL; voltage leads current by 90°.
  • Capacitor: XC = 1/(2πfC); voltage lags current by 90°.
  • Impedance: Z = √(R² + (Xᵟ − XC)²) — voltages add as vectors, never algebraically.
  • Oscillating circuit: an LC pair exchanges energy at f = 1/(2π√LC).
  • Resonance: current peaks when Xᵟ = XC, i.e. at f₀ = 1/(2π√LC) — the basis of radio tuning.